Can you calculate the inverse DTFT of i(d/dw)Y(eiw) in terms of y[n]?

[nacreous]

Homework Statement

There is a signal y[n] with a differentiable DTFT Y(e^iw). Find the inverse DTFT of i(d/dw)Y(e^iw) in terms of y[n] (where of course i = √-1).

Homework Equations

Sifting property ∫e^iwndw = 2π*δ[n] from [-π,π] (integral a) leads to ∫Y(e^iwn)dw = 2π*y[n] from [-π,π] (integral b) which I derived in a previous question.

The Attempt at a Solution

Not sure where to start as I don't actually understand what i(d/dw) is. Is it a transposition of some sort? How do I include i(d/dw) into integral b above? It isn't true that n = 1 in this case...is it? Am I perceiving this to be more complicated than it is?

 

[John Park]

i(d/dw) is simply an operator: it means differentiate w.r.t. w and multiply the result by i.