Calculating Joules to Compress Air: Dan's Question

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SUMMARY

This discussion focuses on calculating the energy required to compress air in a tank, specifically a 4-gallon tank of air at standard temperature and pressure (STP) to a pressure of 300 kPa. The formula used is P=nRT/V, and the integration of this function over the specified volume yields an energy requirement of 5520.035 Joules for the compression process. Additionally, it is clarified that when the gas expands back to ambient pressure, the volume increases to 16 gallons, not 12 gallons, due to the absolute pressure consideration.

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  • Understanding of the Ideal Gas Law (P=nRT/V)
  • Basic knowledge of thermodynamics and energy calculations
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  • Experience with integration in calculus for energy calculations
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Dalau
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So here I am at work, and the go-to people for physics are away. Here is the problem I am trying to figure out:

I'm wondering how much energy it takes to compress a certain amount of
air at a certain temperature, to a certain pressure. For example, let's
say I had a 4-gallon tank of STP air and I wanted to add air until the
pressure inside the tank reached 300 kPa. How much energy, in joules,
would it require to do this?
-Danedit: nevermind this thread. Zz gave me a bit of help. If you want, you can still give me some help, but for now, I should be fine, unless I post here again requesting help.
 
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You just do it the opposite way : calculate how much work the tank releases when it vents the gas out.

We have P=nRT/V, so you integrate the function nRT/V dV with 4 galon and 12 galon as the endpoints of the interval. 12 galon is the volume the compressed gas expand when it is released.
I am sorry not to have the numerical results for you.
 
In this case, consider the atmosphere equals to 100kPa, then the energy needed to compress air into a 4 gallon tank to 300kPa is 5520.035 Joules.
 
I ve got a question:

The gas is compressed to 300kPa with the volume of 1 gallon. At ambient condition, the pressure is 100kPa, and the absolute value of 300kPa must be 400kPa, so that the volume of gas will be 16 gallons, not just 12 gallons after being expanded to ambient pressure.
I am right?
 

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