Calculating Limits and Integrals: Tips and Tricks for Solving Tough Problems

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SUMMARY

The discussion centers on evaluating the limit of the expression lim (x/(x-3)) * (Integral of sin(t)/t dt from 3 to x) as x approaches 3. The sine integral function, defined as Si(x) = ∫(0 to x) (sin t)/t dt, is crucial for simplifying the limit. The limit can be computed using the derivative of the sine integral at x=3, resulting in the final answer of 3 * (sin 3)/3 = sin 3. L'Hôpital's rule is also suggested as an alternative method for solving the problem.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with definite integrals and the sine integral function
  • Knowledge of L'Hôpital's rule for evaluating indeterminate forms
  • Basic differentiation techniques
NEXT STEPS
  • Study the properties and applications of the sine integral function Si(x)
  • Learn how to apply L'Hôpital's rule to various types of limits
  • Practice evaluating limits involving definite integrals
  • Explore advanced techniques in calculus for solving complex integrals
USEFUL FOR

Students in calculus courses, particularly those tackling limits and integrals, as well as educators seeking to clarify these concepts for their students.

TheMadHathor
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"Some really hard problems" That is exactly what our teacher wrote on the top of this worksheet we got for homework. I'm in Calc AB and our teacher gave us 12 really evil problems. I'm stuck just on the first problem:

Evaluate lim (x/x-3)(Intergral of sint/t dt from 3->x)
x->3

Sorry if the notation is kind of weird, I don't know how to get half these symbols on the computer.

Anyway, I first tried to find the limit of just x/x-3 and it's undefined. Then I tried finding the intergral of sint/t dt but it just kept going around in a circle from (ln t)(sin t)-the intergral of ln t (-cos t)-(1/t)(-cos t)-the intergral of 1/t sin t...and so forth. I believe i saw somewhere that if an intergral keeps repeating it's undefined, but my teacher hinted that there's a definite solution to it.

Can someone help me? This assignment is due Thursday, and I haven't a clue as how to go about solving these. I'll need help on some of the other problems too, which I'll post later. Someone please respond soon! I don't want to fail! :cry: :biggrin:
 
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TheMadHathor said:
Can someone help me? This assignment is due Thursday, and I haven't a clue as how to go about solving these. I'll need help on some of the other problems too, which I'll post later. Someone please respond soon! I don't want to fail! :cry: :biggrin:

I'm trying to help u:Hopefully i' right.I'm not a mathematician. :-p
\lim_{x\rightarrow 3}\frac{x}{x-3}\int_{3}^{x} \frac{\sin t}{t} dt=...??( 1)

Define this function (called "sine integral")
Si(x)=:\int_{0}^{x} \frac{\sin t}{t} dt
Using the additivity property of the definite integral,it's not hard to show that the integral in (1) is
Si(x)-Si(3)

Your limit becomes
\lim_{x\rightarrow 3} x\frac{Si(x)-Si(3)}{x-3}
Now use the definition for the derivative of a function in one point to get the limit
3 \frac{d Si(x)}{dx}|_{x=3}.

Use the fact that:
\lim_{t\rightarrow 0}\frac{\sin t}{t} =1 and the fact that:
\frac{d}{dx}[\int_{a}^{x} f(t) dt]=f(x)

To get the answer:
3\frac{\sin 3}{3}=\sin 3

However,i'm not sure on this result.Mathematicians on this forum can correct my mistakes and if,by chance,everything i did is correct,supply you with rigurous mathematical founding to my calculations.

Daniel.
 
... or, you could just apply l'Hopital directly to your expression - integral and all! :-)
 
Tide said:
... or, you could just apply l'Hopital directly to your expression - integral and all! :-)

I don't know,Tide,my approach seems elegant. :approve: No L'Hospital,no tricky differentiations,just definitions and a simple limit. :wink:

Daniel.
 
dextercioby said:
I don't know,Tide,my approach seems elegant. :approve: No L'Hospital,no tricky differentiations,just definitions and a simple limit. :wink:

Daniel.

A thousand pardons! I failed to recognize a masterpiece when I saw it! :blushing:
 
Anyways, the lesson to be learned is that, no matter how complicated it looks,

<br /> \int_a^x f(t) \, dt<br />

is merely a function of x.
 
Thanks! L'Hopital's theorem makes it so much easier, duh! It was the next section in our book! :biggrin:
 
TheMadHathor said:
Thanks! L'Hopital's theorem makes it so much easier, duh! It was the next section in our book! :biggrin:

So much for the elegance in mathematics... Anyway,u're free to post your problems.

Daniel.
 

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