Calculating Limits: Need Help Solving These!

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SUMMARY

This discussion focuses on calculating limits in calculus, specifically addressing three limit problems as x approaches 0. The first limit, lim |x| / (x + 1) as x approaches 0, evaluates to 0. The second limit, lim (1 + sin x)^(1/x) as x approaches 0, is solved using the exponential limit property, resulting in e. The third limit, lim (e^(2 sin x) - e^(sin x)) / (sin 2x) as x approaches 0, is simplified using the substitution y = sin(x) and results in 2.

PREREQUISITES
  • Understanding of basic calculus concepts, particularly limits.
  • Familiarity with the properties of exponential functions.
  • Knowledge of the Squeeze Theorem and its application in limit calculations.
  • Experience with trigonometric limits and their behavior as x approaches 0.
NEXT STEPS
  • Study the application of the Squeeze Theorem in limit problems.
  • Learn about the properties of exponential functions and their limits.
  • Explore advanced limit techniques, including L'Hôpital's Rule and Taylor series expansions.
  • Practice solving trigonometric limits, particularly those involving sin(x) and cos(x) as x approaches 0.
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Students in calculus courses, educators teaching limit concepts, and anyone seeking to strengthen their understanding of limit calculations in mathematics.

n3ll4f
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Hi

I´m new here and i´m new on this course. I have a test tomorrow and i need to know how to calculate limits, but i have some that i can´t solve, please can you solve it, ins´t homework, it´s only to learn (don´t use l'hospital):

lim | x | / (x + 1)
x->0


lim (1 + sin x)^(1/x)
x->0


lim (e^(2 sin x) - e^(sin x)) / (sin 2x)
x->0


Thanks in advance
 
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lim | x | / (x + 1)
x->0

Show the function is continuous at 0
limit of a continuous function is an evaluation

lim (1 + sin x)^(1/x)
x->0

rewrite as

lim (1 + x[sin x/x])^(1/x)
x->0
use
lim (1 + x*a)^(1/x)=exp(a)
x->0
and composition or squish theorem

lim (e^(2 sin x) - e^(sin x)) / (sin 2x)
x->0

rewrite as
lim (e^(2 y) - e^y) / y
y->sin(x)->0

and

(e^(2 y) - e^y)=(e^y-1)^2+(e^y-1)

and

lim (e^x- 1) / x=1
x->0
 

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