Calculating Limits: Refresh Your Memory

[Ted123]

Show that, with $t\in [0,1]$ : $$\lim_{n\to\infty} \frac{\sin(nt)}{n}=0$$

This is easy but I've forgotten how to calculate limits. Can anyone jog my memory?

 

[MaxManus]

Not sure, but how can the limit be something else when |sin| <=1 and n goes to infinity?