Calculating Linear Speed of Test Tube in Centrifuge

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SUMMARY

The linear speed of the bottom of a test tube in a centrifuge can be calculated using the formula for centripetal acceleration, which is given by the equation \( a_c = \frac{v^2}{r} \). In this case, the centripetal acceleration is 5.3×104 times the acceleration due to gravity (9.81 m/s2), resulting in a value of approximately 519,930 m/s2. Given the radius (distance from the axis of rotation) of 7.3 meters, the linear speed can be derived as 1900 m/s, confirming the calculations presented in the discussion.

PREREQUISITES
  • Centripetal acceleration formula
  • Understanding of linear speed calculations
  • Basic physics concepts of motion
  • Knowledge of gravitational acceleration (9.81 m/s2)
NEXT STEPS
  • Study the derivation of centripetal acceleration equations
  • Learn about the relationship between linear speed and radius in circular motion
  • Explore practical applications of centrifuges in laboratory settings
  • Investigate the effects of varying radius on linear speed in rotational systems
USEFUL FOR

Students in physics courses, educators teaching mechanics, and professionals working with centrifuge technology will benefit from this discussion.

mwegimont
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Homework Statement



Find the linear speed of the bottom of a test tube in a centrifuge if the centripetal acceleration there is 5.3×104 times the acceleration of gravity. The distance from the axis of rotation to the bottom of the test tube is 7.3 .

Homework Equations




I have gotten answers of 1900 and 223 m/s.I cannot figure out how to do this problem
 
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Show how you arrived at those answers. What are the units for the distance? What's the formula for centripetal acceleration?
 

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