Calculating Magnetic Dipole Moment & Torque of Coil in Magnetic Field

AI Thread Summary
The discussion focuses on calculating the magnetic dipole moment and torque of a circular coil in a magnetic field. The coil has 20 turns, a radius of 12.8 cm, and carries a current of 2.70 A in a 60.0 mT magnetic field, with an initial angle of 26.0 degrees between the magnetic moment and the field. The magnetic dipole moment was calculated correctly as 2.78 A*m^2, and the torque was found to be 7.31E-2 N*m using the formula T=μBsin(θ). The main challenge lies in determining the work required to rotate the coil so that the magnetic field aligns with the plane of the coil. Further clarification is needed on how to approach the work calculation for part three.
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Homework Statement



A circular coil having 20 turns and a radius of R = 12.8 cm carries a current of 2.70 A. It is placed in a uniform magnetic field of 60.0 mT. The initial angle between the magnetic moment of the coil μ and the magnetic field B is 26.0o.
1)Calculate the magnetic dipole moment of the coil.
2)What is the magnitude of the torque acting on the coil?
3)How much work is required to rotate the coil so that the B-field lies in the plane of the coil?


Homework Equations



x=uo M/B

The Attempt at a Solution


so I solved for uo by using the equation uo=NAI and got 2.779 but now I do not know what to do and if the equation my professor gave is correct. Then on parts 2 and 3 I don't know where to begin.
 
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I got part one and part 2. I think I misunderstood the problem because part one is asking for uo which I solved for and got 2.78 A*m^2 which was correct. Then with this I can find the torque for part 2 with the equation T=uoBsin(theta). So I used this equation and I got 7.31E-2 N*m which was correct. Now I have part 3-how much work is needed-to solve for and i am not sure what I am supposed to do.
 
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