Calculating Magnetic Force on a Moving Charge near an Infinite Straight Wire

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SUMMARY

The discussion focuses on calculating the magnetic force on a moving charge near an infinite straight wire carrying a current of 73 x 107 amps. The magnetic field (B) is calculated using the formula B = (μ0I)/(2πr), resulting in a value of 29.89 T. The magnetic force (FB) is then determined using FB = qvBsin(θ), where θ is the angle between the velocity vector and the magnetic field direction. The final answer for the magnetic force is confirmed to be 139.51 N, emphasizing the importance of including the sine component in the calculation.

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Homework Statement


An infinite straight wire is located at origin of a coordinate system. It has a large current of 73 x 107 amps running positive z direction. A point charge of -4 micro-Coulombs is moving at 3 x 106 m/s in positive x direction at point x=1.9 m, y=4.5 m. What is magnitude of magnetic force on this charge in Newtons? Answer is 139.51.

Homework Equations


B=[tex]\mu0[/tex]I/(2[tex]\pi[/tex]r)
FB=qvBsin[tex]\theta[/tex]

The Attempt at a Solution


B=(4[tex]\pi[/tex] x 10-7 Tm/A)(73 x 107 A)/(2[tex]\pi[/tex])(4.88m)=29.89 T
FB=(4 x 10-6 C)(3 x 106 m/s)(29.89 T)sin(67.11)
 
Last edited:
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θ is the angle from the direction of vector qv and to the direction of vector B.

sinθ is missing from your answer.
 
Very simple: you didn't took into account that the velocity is not totally orthogonal to the direction of the magnetic field, i.e. you didn't multiplied with sinLaTeX Code: \\theta.

The direction of the magnetic field is tangential to the radius, your radius is the vector (1.9, 4.5)m, you need to find the orthogonal direction to this vector.

**@SammyS beat me to it :)
 

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