Calculating Man's Northward Distance Traveled with Vector Components

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SUMMARY

To calculate the northward distance traveled by a man running at a velocity of 5 m/s at an angle of 25 degrees north of east for 10 minutes, one must utilize vector components. The northward component of the velocity can be determined using the formula 5(sin 25) m/s. After converting the time to seconds (600 seconds), the distance traveled north can be calculated using the equation distance = velocity x time, resulting in a final northward distance of approximately 25 m.

PREREQUISITES
  • Understanding of vector components in physics
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with basic kinematic equations
  • Ability to convert time units (minutes to seconds)
NEXT STEPS
  • Learn about vector decomposition in physics
  • Study the application of trigonometric functions in motion problems
  • Explore kinematic equations for two-dimensional motion
  • Practice problems involving displacement and velocity components
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Students studying physics, particularly those focusing on kinematics and vector analysis, as well as educators looking for examples of vector component calculations in real-world scenarios.

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Homework Statement



Man runs with velocity = 5m/s @ 25 degrees north of east for 10 minutes.
How far to the north of his starting position does he end up?

Homework Equations





The Attempt at a Solution


I know this has got to be the easiest problem to solve but I am not getting it. this is what I did.

It asked for how far to the north, so I assumed they were looking for a final position. I used vector components (5cos25)i + 5(sin25)j, but I don't know how to solve for the distance x. I know there's a formula v = x / t but that didnt help.
 
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Vector components is the way to go. They only ask for the distance traveled North, so use the component of the velocity along the y-axis (North) and from that magnitude (speed), you can use your Speed = distance/time equation.

i.e. x = vt

(remember to convert time to seconds).

OR

You could work out his displacement, using Velocity = displacement/time, i.e. Displacement = velocity x time and then break the displacement vector down into components.

Both should give you the same answer.
 

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