Adding vector components in two dimensions

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Homework Help Overview

The problem involves a plane flying south at a speed of 600 km/h while encountering a southwestern wind of 100 km/h. Participants are discussing how to determine the resultant velocity of the plane, including both its magnitude and direction.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are breaking down the wind vector into its components and attempting to apply trigonometric functions to find the resultant velocity. There are questions about the correctness of the angle used for the southwestern wind and the subsequent calculations. Some participants express uncertainty regarding the answers found on other websites.

Discussion Status

There is ongoing exploration of the problem with participants sharing their calculations and questioning the accuracy of their results. Some express agreement with the possibility of a typo in the expected answer, while others are seeking clarification on discrepancies found in external sources.

Contextual Notes

Participants mention that they have encountered differing answers on other educational websites, which raises questions about the assumptions made in the problem setup and the interpretation of the wind's direction.

Square1
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Homework Statement


A plane flies 600km/h south. The plane encounters a southwestern wind of 100km/h.

Homework Equations


What is the velocity (magnitude and direction) of the plane

The Attempt at a Solution


What I did was break the 100km southwestern vector into its components. 100*cos45 = 70.71 (45 because southwestern wind is 45deg?). This will be both north and east component since it is 45 45 90 triangle that is being used.

Then I subtract 70.71 north component from 600 original vector = 529.29
Using the new 529.29 south component, and the remaining east pointing 70.71 component, I use phythagoras to find the resulting velocity vector.
I get 534. Answer is 543.

As for the heading, I get 7.61deg, which is inline with the answer.
 
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Square1 said:

Homework Statement


A plane flies 600km/h south. The plane encounters a southwestern wind of 100km/h.

Homework Equations


What is the velocity (magnitude and direction) of the plane

The Attempt at a Solution


What I did was break the 100km southwestern vector into its components. 100*cos45 = 70.71 (45 because southwestern wind is 45deg?). This will be both north and east component since it is 45 45 90 triangle that is being used.

Then I subtract 70.71 north component from 600 original vector = 529.29
Using the new 529.29 south component, and the remaining east pointing 70.71 component, I use phythagoras to find the resulting velocity vector.
I get 534. Answer is 543.

As for the heading, I get 7.61deg, which is inline with the answer.
I agree with your answer. Must be a typo.
 
Square1 said:
I googled "plane flies in south direction..etc" for similar questions though, and I find on two websites that I still can't get matching answers.
ex: http://www.jiskha.com/display.cgi?id=1254021349
Not sure what you are saying. Do you mean that you submitted an answer to the question there and were told your answer is wrong?
 
No no just that i tried googling that particular question assuming its a "stock question" and people have asked it in the past. I still don't get the same answer as people that have tried to help others on other websites.
 
Square1 said:
No no just that i tried googling that particular question assuming its a "stock question" and people have asked it in the past. I still don't get the same answer as people that have tried to help others on other websites.
Well, the first answer to the question at that link was wrong. It took the wind as from NE instead of SW, so got an answer greater than 515, which is clearly impossible.
 
Oh yea... haha...

Ok well...hopefully was a typo...534...543...thank you.
 

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