Calculating Mass and Velocity in Elastic Collisions: Lab Cart A and B Example

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Homework Help Overview

The discussion revolves around an elastic collision scenario involving two lab carts, A and B, where cart A collides with cart B, and subsequently, cart B collides with cart C. The original poster seeks to determine the mass of cart B and its velocity after the collision with cart A.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply conservation of momentum and energy principles to solve for the unknown mass and velocity. They express uncertainty about their calculations and seek validation of their method.

Discussion Status

Some participants have acknowledged the original poster's equations and indicated that they have two equations with two unknowns to solve. There is ongoing dialogue about the clarity of variable usage and the correctness of the approach taken.

Contextual Notes

Participants are discussing the implications of variable naming conventions, particularly regarding the use of symbols for different velocities in the context of multiple collisions. There is no consensus on the correctness of the original poster's method yet.

runningirl
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Homework Statement



Lab cart A(v=1.5 m/s; m=.25 kg) collides elastically with lab cart B (v=0m/s; m=?). After the collision, the velocity of cart A is -.67 m/s. Cart B then goes on to have a sticky collision with cart C (v=0 m/s; m=.50 kg). After the sticky collision, the velocity of the combined carts B and C is 0.47 m/s. What is the mass of cart B? What as the velocity of cart B right after cart A collided with it?




3. The Attempt at a Solution

m1v1+m2v2=m1vf1+m2vf2

.25(1.5)+m(0)=.25(-.67)+m(vf2)

mv1+.5(0)=(m+.5)(.47)

i wanted to substitute m or v to solve for them each...

i got m=.65 kg and v=.83 m/s.

but i wasn't sure if my method was correct.
 
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runningirl said:
Lab cart A(v=1.5 m/s; m=.25 kg) collides elastically with lab cart B (v=0m/s; m=?). After the collision, the velocity of cart A is -.67 m/s. Cart B then goes on to have a sticky collision with cart C (v=0 m/s; m=.50 kg). After the sticky collision, the velocity of the combined carts B and C is 0.47 m/s. What is the mass of cart B? What as the velocity of cart B right after cart A collided with it?

m1v1+m2v2=m1vf1+m2vf2

.25(1.5)+m(0)=.25(-.67)+m(vf2)

mv1+.5(0)=(m+.5)(.47)

i wanted to substitute m or v to solve for them each...

i got m=.65 kg and v=.83 m/s.
.

you see, the velocity of the cart B after it collides with cart A (vf2) is same as the velocity of the cart B before it collides with cart C (v1) which I have highlighted above. Since you have already used the symbol v1 as the velocity of the cart A before it collides with the cart B, don't use it again for the velocity of the cart B before it collides
with cart C.
 
thanks. but is my method correct?
 
yes, so you have now two equations and two unknowns, mass of cart B (m) and the velocity of the cart B after the collision with cart A and before the collision with cart C (vf1). so solve for these.
 

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