Calculating mass of air displaced in compressor.

Click For Summary
SUMMARY

The discussion focuses on calculating the mass of air displaced in a pneumatic pump experiment using the equations PV = mRT and P1V1n = P2V2n. The theoretical displacement is established at 106 l/min, leading to a volume of 53 liters for a 30-second cycle. The relevance of the second equation is questioned, with emphasis on determining the process type (isothermal or adiabatic) after conducting the experiment. The specific gas constant R for air is highlighted as crucial for accurate calculations.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = mRT)
  • Knowledge of pneumatic systems and compressor operations
  • Familiarity with isothermal and adiabatic processes
  • Basic principles of thermodynamics
NEXT STEPS
  • Research the application of the Ideal Gas Law in real-world scenarios
  • Study the differences between isothermal and adiabatic processes
  • Learn about the specific gas constant for air and its implications in calculations
  • Explore experimental methods for measuring air displacement in compressors
USEFUL FOR

Students in engineering or physics, particularly those studying thermodynamics and fluid mechanics, as well as professionals involved in pneumatic system design and analysis.

SherlockOhms
Messages
309
Reaction score
0

Homework Statement


So, this question is to do with an experiment which investigates the operations of a pneumatic pump. You're asked to find the mass of air displaced in each 30 second period using the atmospheric pressure, temperature and theoretical displacement of the compressor. Also, you are told to use 2 of following equations: PV = mRT and P1V1n = P2V2n.


Homework Equations


Given in question.


The Attempt at a Solution


Well, the theoretical displacement is given as 106 l/min. Thus for a 30 second cycle, V = 53 l. Does it not make sense just to use PV = mRT for this? How is P1V1n = P2V2n relevant? Thanks.
 
Physics news on Phys.org
<< Does it not make sense just to use PV = mRT for this? >>

Don't know why not.

Use dm/dt = (p/RT) dv/dt. R is specific to air of course, not the universal gas constant.

If n = 1, p^n v^n = RT denotes an isothermal process. If n = cp/cv it's an adiabatic process.
You don't know if it's either one so that's another reason I don't see any point in this equation here.
 
I guess, once I carry out the experiment I can see my values for n and then judge whether it's an isothermal or adiabatic process. Does that sound reasonable?
<<If n = 1, p^n v^n = RT>>
Why is it p^n v^n = RT and not p^n v^n = mRT? Also, why is P raised to the power of n? Think I've lost track of you.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
9
Views
2K
Replies
6
Views
2K
Replies
11
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
6
Views
8K
  • · Replies 3 ·
Replies
3
Views
3K