Calculating Mass of Stars in a Binary System

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Homework Help Overview

The discussion revolves around calculating the mass of stars in a binary system, specifically focusing on two stars of equal mass that orbit a common center. The problem involves understanding the gravitational forces and orbital mechanics involved in such a system.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of Kepler's laws and gravitational equations to determine the mass of the stars. There are discussions about potential algebraic mistakes and the correct interpretation of the radius in the context of the binary system.

Discussion Status

The discussion is ongoing, with participants questioning the accuracy of their calculations and the assumptions regarding the radius used in the equations. Some guidance has been provided regarding the interpretation of the distance between the stars and its relation to the radius.

Contextual Notes

Participants are navigating through the complexities of orbital mechanics and gravitational equations, with some confusion about the definitions of radius and distance in the context of binary star systems. There is also a reference to a textbook answer, which may influence their understanding of correctness.

chazgurl4life
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Q:
Suppose that a binary star system consists of two stars of equal mass. They are observed to be separated by 340 million kilometers and take 5.0 Earth years to orbit about a point midway between them. What is the mass of each?
I figured out that:
mass=4pi^2(radius)^2/Gravitational Force(#of years)*(distance)2
m= [4(3.14)^2(3.3x10^29)^3]/[(6.67x10^-11){(8.0 years)(3.4x10^7}^2] =3.33x10^29 then (3.33x10^29)/2 = 1.7x10^29

I don't know what I'm doing wrong here. Any ideas?
 
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chazgurl4life said:
Q:
mass=4pi^2(radius)^2/Gravitational Force(#of years)*(distance)2

Maybe an algebra mistake in getting to this point. Should be:
mass=4pi^2(radius)^3/(Gravitational Force(#of years*seconds per year)^2)

How did you know your answer was wrong? It's very close to correct. Does the back of the book give the answer?
 
Last edited:
so if i reply this equation it comes out as:
m=4pi^2(3.3x10^29)^3/6.67e-11(5yearsx 3.155815296E7 sec per yr)^2

is that right? or am i using the wrong radius? isn't the radius half the distance between the two stars? if that's true than the radius id 170 million, isn't it? I am so confused!
 
Last edited:
Where did you get 3.3 x 10^29. They give you the distance of 340,000,000 million kilometers. This becomes your a or radius (3.4 x 10^11 meters)

It's not half the distance between the 2 stars since. Pretend 1 star is still, and the other orbits it. It will trace an orbit whose diameter is twice the distance between the 2 stars. Therefore, the distance between the 2 stars becomes the radius, or semi-major axis in this problem.
 

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