Kepler's 3rd law and a binary system

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SUMMARY

The discussion revolves around the application of Kepler's 3rd law to the binary star system 55 Cancri, specifically analyzing the radial velocity data of its three exoplanets: 55 Cancri b, c, and d. The observed parameters include velocities of 71.8 m/s, 10.0 m/s, and 47.2 m/s, with periods of 14.6 days, 43.9 days, and 521.8 days, respectively. The mass function equation used is ##\frac{PV_{obs}^3}{2\pi G}=\frac{M_2sin^3(i)}{(M_1+M_2)}##, leading to confusion regarding the mass relationship between the stars. The discussion clarifies that the mass of the primary star (M1) is significantly larger than that of the secondary star (M2), despite the initial assumptions of the poster.

PREREQUISITES
  • Understanding of Kepler's laws of planetary motion
  • Familiarity with radial velocity methods in exoplanet detection
  • Basic knowledge of binary star systems and mass functions
  • Proficiency in algebraic manipulation of equations in astrophysics
NEXT STEPS
  • Study the derivation of the mass function in binary star systems
  • Explore the impact of orbital inclination on mass calculations
  • Learn about the radial velocity method for exoplanet detection
  • Investigate the dynamics of coplanar and circular orbits in binary systems
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Astronomy students, astrophysicists, and researchers interested in exoplanet dynamics and binary star systems will benefit from this discussion.

Taylor_1989
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Homework Statement


I am having a issue with the question, when I check the solution to the problem, I can't seem to make sense of how they have derived there equation.

Q: By analyzing the superposition of frequencies and amplitudes in the radial velocity data for a star 55 Cancri A, the first three exoplanets in the system were deduced. The star was found ti have the following observed parameters: 55 Cancri b corresponds to ##V_{obs}=71.8ms^m{-s}## and a ##P=14.6## days, 55 Cancri c corresponds to ##V_{obs}=10.0ms^{-s}##, ##P=43.9## days and 55 Cancri d corresponds to ##V_{obs}=47.2^m{-s}##, and ##P=5218## days. Assuming the orbits are coplanar and circular, determin, (i) which planet is furthest from the star, (ii) which planet has the lowest mass and (iii) which planet has the highest mass.

There equation for the solution is

$$M_p=\left(\frac{PM_s^2}{2\pi G}\right)\cdot \frac{V_{\left\{obs\right\}\:}}{sin\left(i\right)\:}$$

Homework Equations



Mass function
##\frac{PV_{obs}^3}{2\pi G}=\frac{M_2sin^3\left(i\right)}{\left(M_1+M_2\right)}##
link to full derivation: https://imagine.gsfc.nasa.gov/features/yba/CygX1_mass/binary/equation_derive.html

The Attempt at a Solution



binary_orbit.png
[/B]
I am slightly confused by there solution because if I were to rearrange the equation mass function to make ##M_2## the subject I get the following

##M_2=\left(\frac{PM_1^2}{2\pi G}\right)^{\frac{1}{3}}\cdot \frac{V_{obs}}{sin\left(i\right)}##

which it the same as the equation given in the solution, but my assumption is that ##M_1>>M_2##

but this contradicts the diagram that I have shown because m1 is orbiting m2 which make m2 the larger of the two stars. This make me think maybe I am misunderstanding either the question, or the physics.

Any advice would be much appreciated and thank in advance
 

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Can't you just swap m1 and m2 in the diagram? It shouldn't matter, the situation is symmetric.
 
I think you are over-thinking this. Ignore the fact that it is a binary star - the stellar companion is so far away that it has a negligible influence on the time scales we are talking about. Just consider it a single star with three planets orbiting it, all of which are much less massive than the star. Then what do you get?
 

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