Calculating Max Compression of Massless Hookslaw Spring

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joemama69
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Homework Statement



A massless hooksw law spring has a unstretched length of L, when a mass m is ploaced on it, and slowly lowered until the mass is at rest, the spring is queezed to a length of x. the mass is then dropped on the spring from a height of h, use energ methods

what is the length of the spring at maximum compression as a result of the mass dropping on it

Homework Equations





The Attempt at a Solution



mgh = -mgs + .5ks2

s = -mg + or -(((mg)2 - 4(.5k)(mgh))/k).5

if this is correct
 

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The question is worded aquardly, but I think you're on the right path with your firse equation. Now you need to write the spring constant k in terms of other parameters you have in your problem.

Also, you get two anilytical solutions. Can you think which sollution is correct? What does your non-physical solution correspond do?
 
what would be the benefit from solving for the spring constant

it asks for the length of the spring at compression s
 
joemama69 said:
what would be the benefit from solving for the spring constant

That way the spring constant is expressed in terms of other known parameters.
 
k = (2mgs - 2mgh)s2 = 2mg(s-h)/s2

i still don't understand how that helps, what would i use it for now