Calculating Maximum Linear Charge Density in Geiger Tube

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SUMMARY

The discussion focuses on calculating the maximum linear charge density in a Geiger tube designed for radiation detection. The critical parameters include a wire diameter of 0.450 mm and an inside tube diameter of 4.20 cm, with an electric field threshold of 5.55 x 106 N/C for gas breakdown. The key insight is that the radius of the wire is used for calculations because the electric field is strongest at the wire's surface, preventing electrical discharge. The cylinder's radius serves as additional context but does not influence the charge density calculation.

PREREQUISITES
  • Understanding of electric fields and charge density
  • Familiarity with Geiger tube design principles
  • Knowledge of cylindrical coordinates in physics
  • Basic concepts of gas breakdown and ionization
NEXT STEPS
  • Study the principles of electric fields around cylindrical conductors
  • Research the breakdown voltage of gases in various conditions
  • Learn about the design and operation of Geiger-Müller counters
  • Explore calculations involving charge density and electric field strength
USEFUL FOR

Students in nuclear physics, engineers designing radiation detection instruments, and anyone interested in the principles of electric fields and charge density in cylindrical geometries.

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Homework Statement



For your senior project, you are designing a Geiger tube for detecting radiation in the nuclear physics laboratory. This instrument will consist of a long metal cylindrical tube that has a long straight metal wire running down its central axis. The diameter of the wire will be 0.450 mm and the inside diameter of the tube will be 4.20 cm. The tube is to be filled with a dilute gas in which an electrical discharge (breakdown of the gas) occurs when the electric field reaches 5.55 106 N/C. Determine the maximum linear charge density on the wire if breakdown of the gas is not to happen. Assume that the tube and the wire are infinitely long.


I'm not really interested in the answer, it's just the process I don't know how to do for this problem.
 
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actually I found out how to do it, but can someone explain to me why we use the radius of the wire instead of cylinder to get our answer? What's the point of giving the radius of the cylinder then?
 


XP I suppose I'm probably too late to be helpful now, but it's because the electrical field is strongest by the surface of the wire. If we used the radius of the cylinder, the electrical field everywhere else on the inside would be strong enough to cause an electrical discharge. The only point of it is to mislead I guess.
 

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