Calculating Maximum Resistance & Inductance for Theater Light Dimmer

Click For Summary
SUMMARY

The discussion focuses on calculating the maximum inductance (Lmax) and resistance (Rmax) for a theater light dimmer circuit. Given a 120 V (rms) supply at 60.0 Hz and a lightbulb rated at 120 V, 1300 W, the required Lmax to vary energy dissipation by a factor of 4 is determined to be 0.059 H. The relationship between power, resistance, and inductance is established using the equations P = (i^2)(R) and P = V^2 / R, leading to the conclusion that Lmax can be derived from the maximum resistance in the circuit.

PREREQUISITES
  • Understanding of RLC circuit theory
  • Familiarity with electrical power equations (P = V^2 / R)
  • Knowledge of inductance and resistance concepts
  • Basic grasp of alternating current (AC) principles
NEXT STEPS
  • Study the principles of RLC circuit analysis
  • Learn about the effects of inductance on AC circuits
  • Explore variable resistor applications in dimming circuits
  • Investigate the relationship between power factor and circuit efficiency
USEFUL FOR

Electrical engineering students, theater technicians, and professionals involved in lighting design and control systems will benefit from this discussion.

reising1
Messages
54
Reaction score
0

Homework Statement



A typical "light dimmer" used to dim the stage lights in a theater consists of a variable inductor L (whose inductance is adjustable between zero and Lmax) connected in series with a lightbulb. The electrical supply is 120 V (rms) at 60.0 Hz; the lightbulb is rated as 120 V, 1300 W. (a) What Lmax is required if the rate of energy dissipation in the lightbulb is to be varied by a factor of 4 from its upper limit of 1300 W? Assume that the resistance of the lightbulb is independent of its temperature. (b) What would be the maximum resistance of a variable resistor (adjustable between zero and Rmax) which can be used in place of an inductor?

Homework Equations



I know the equations for RLC circuits, and I know P = (i^2)(R)

The Attempt at a Solution



I'm really just stuck. I don't really understand the question. Are we increasing it by a factor of 4 or decreasing it? Can someone get me started on the right track?
 
Physics news on Phys.org
I also know that P = V^2 / R

Taking the ratio of Pmax to Pmin we get

Pmax/Pmin = (Imax / Imin)^2 = ( (E/Zmax) / (E/Zmin) )^2 = 4

So

(sqrt( (R^2) + ((w*Lmax)^2) ) / R)^2 = 4

which implies that

Lmax = R / w (when we solve for Lmax in the above equation)

Thus, pluggin in for P = V^2 / R

we get ( (2V^2 / P) / w) = Lmax

Solving, I get Lmax = .059. Does this seem correct?

Now what about part b. Not sure about that one.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
Replies
11
Views
5K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
9K
Replies
1
Views
6K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K