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A light-dimmer switch with a potentiometer

  1. Apr 24, 2016 #1
    1. The problem statement, all variables and given/known data
    Some light-dimmer switches use a variable resistor as shown in figure. The slide moves from position x = 0 to x = 1, and the resistance up to slide position x is proportional to x (the total resistance is Rpot = 100Ω at x = 1). What is the power expended in the light bulb if x = 0.5?

    2. Relevant equations
    Rseries = R1 + R2 + ...
    Rparallel = 1 / (1 / R1 + 1 / R2 + ...)
    P = V2 / R = I2R

    3. The attempt at a solution
    I tried first to obtain the total resistance, which is 50 + 1 / (1 / 50 + 1 / 205), and use this number to divide the voltage squared in order to get the power, but this is not correct. I don't know what I'm missing here. Any help will be appreciated.
     

    Attached Files:

  2. jcsd
  3. Apr 24, 2016 #2

    gneill

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    Staff: Mentor

    Hi Asylum, Welcome to Physics Forums.

    Were you given any information about the bulb itself? It's resistance or power rating?
     
  4. Apr 24, 2016 #3
    Hello, I think the resistance for the bulb is 205Ω.
     
  5. Apr 24, 2016 #4

    gneill

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    Staff: Mentor

    Okay, that would make it a 70 Watt bulb running at 120 V.

    What you're looking to find is the power dissipated by the bulb resistance alone. To that end you'll need to find either the voltage across it, the current through it, or both.
     
  6. Apr 24, 2016 #5
    Thank you, I will try that now.
     
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