Is the spring constant given or did you calculate it?senoltreble said:
I understand the question.senoltreble said:
You think you found the spring constant, but you made an error. The distance given is the maximum stretch of the spring from its unstretched position. So where's the new equilibrium point? Use that to find the correct value of the spring constant.
The maximum speed of a 65.0- fish on an ideal spring can be calculated using the formula v = √(k/m), where v is the maximum speed, k is the spring constant, and m is the mass of the fish.
An ideal spring is a theoretical concept in physics that assumes a spring has no mass, no damping, and obeys Hooke's law perfectly. This means that the force exerted by the spring is directly proportional to the displacement of the object attached to it.
The spring constant for an ideal spring can be determined by dividing the force exerted by the spring by the displacement of the object attached to it. This value remains constant as long as the spring obeys Hooke's law.
No, the maximum speed of a fish on an ideal spring cannot be greater than the speed of light. This is because the speed of light is the ultimate speed limit in the universe and any object that has mass cannot exceed this speed.
Yes, the mass of the fish does affect the maximum speed on an ideal spring. According to the formula v = √(k/m), as the mass of the fish increases, the maximum speed decreases. This means that a heavier fish will have a lower maximum speed on the same ideal spring compared to a lighter fish.