Calculating Min Stopping Distance for Car Traveling at 60 m/s

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Homework Help Overview

The problem involves calculating the minimum stopping distance for a car traveling at a speed of 60 m/s, given a reference stopping distance at 30 m/s. The context includes considerations of reaction time and acceleration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between speed, stopping distance, and acceleration, with attempts to apply relevant equations. Questions arise regarding the inclusion of reaction time and the correct interpretation of variables in the equations.

Discussion Status

Participants are actively engaging with the problem, sharing calculations and questioning the validity of their approaches. Some guidance has been offered regarding the equations to use, but there is no consensus on the correct stopping distance yet.

Contextual Notes

There is mention of a reaction time of 0.50 s and the need to account for distance traveled during this time, which may affect the overall calculations. Participants express uncertainty about their calculations and the application of the equations.

Phoenixtears
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Homework Statement


The minimum stopping distance for a car traveling at a speed of 30 m/s is 60 m, including the distance traveled during the driver's reaction time of 0.50 s.

(a) What is the minimum stopping distance for the same car traveling at a speed of 60 m/s?
m




Homework Equations


Vf^2= V0^2 + 2ax


The Attempt at a Solution


Now I have my equation set up, but I can't figure out the change in x. Instead I have (60m-x) in my equation, but I'm looking for acceleration so that I can use that in my next equation when it comes to going 60 m/s. How is one to find the other x if it is not given?

~Phoenix
 
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The relevant equation should be written as:

Vf2 = Vi2 +2a[tex]\Delta[/tex]x

[tex]\Delta[/tex]x is the distance the car goes to stop.
 
Gotcha... wow, now I feel rather dense. That makes perfect sense- I've no idea why I skipped over that. All right, I worked the equations and got 7.5 m/s/s as my acceleration. I used that in my equation involving 60 m/s (0^2= 60^2 + 2(7.5)x) and got 240 as my answer. Yet this is wrong, is there something in my calculations that is incorrect?
 
Did you include the distance you travel before you hit the brakes?
 
Yes, using the equation: deltax= V0*t + (.5)(a)(t^2). My numbers being: V0=60; t=.5; a=7.5. totalling to 270.94, and yet that did not work either.

(I had tried both answers before)
 
Phoenixtears said:
Yes, using the equation: deltax= V0*t + (.5)(a)(t^2). My numbers being: V0=60; t=.5; a=7.5. totalling to 270.94, and yet that did not work either.

(I had tried both answers before)
The car is not accelerating before the brakes are applied.

The equation you should use is x = vt.
 
Yikes. That's just basic... I think I'm a bit tired. Right, well then, that would mean it travel 60m*.5s leaving 120m total during that time. Adding that to my original 240 brings me to 270m total... well. That was just depressing, as that didn't work. :/ Now something must be wrong. I've done everything wrong along the way, then correcting it, and yet 270 seems as if that is correct...
 
Is the correct answer 210m?
 

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