Calculating Minimum & Maximum Speed for an Icy Curve

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SUMMARY

The discussion focuses on calculating the minimum coefficient of friction required to prevent sliding for a car rounding an icy curve with a radius of 220.0 m at a speed of 21.0 m/s. The minimum coefficient of friction was determined to be 0.205. For the second part, the maximum safe speed on an icy surface, where the coefficient of friction is reduced to one-third (approximately 0.0683), can be calculated using the same formula for centripetal force, leading to a maximum speed of approximately 11.5 m/s.

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  • Familiarity with basic physics equations related to motion
  • Knowledge of how to manipulate equations to solve for variables
  • Experience with calculating coefficients of friction
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physicsgirlie26
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A flat (unbanked) curve on a highway has a radius of 220.0 m. A car rounds the curve at a speed of 21.0 m/s.

What is the minimum coefficient of friction that will prevent sliding?

Suppose the highway is icy and the coefficient of friction between the tires and pavement is only one-third what you found in part A. What should be the maximum speed of the car so it can round the curve safely?




Can someone help me. I don't know what to do for the second part. I found the minimum coefficient to be .205 but i can't find the maximum speed.

Is the equation squareroot of coefficient of friction divided by radius?
 
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How did you get the first part? use the exact same relationship... just use coefficient of friction is 0.205/3. this time you're using the same equation... just solving for v.
 

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