What Minimum Coefficient of Static Friction Prevents Skidding on a Banked Curve?

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SUMMARY

The discussion centers on calculating the minimum coefficient of static friction required to prevent skidding for an automobile rounding a banked curve with a radius of 140m at a speed of 30 m/s, while the curve is designed for a speed of 20 m/s. Key equations include the force of friction (F_fr = μ_kN), the normal force (N = mgcosθ), and the net force equation (∑F_net-x = mv²/r = Nsinθ). Participants emphasize the importance of accurately analyzing the forces acting on the vehicle and suggest revisiting the free body diagram to ensure all forces are accounted for in the calculations.

PREREQUISITES
  • Understanding of Newton's second law (∑F = ma)
  • Knowledge of centripetal force equations (∑F_net-x = mv²/r)
  • Familiarity with free body diagrams in physics
  • Basic trigonometry for resolving forces (N = mgcosθ)
NEXT STEPS
  • Calculate the minimum coefficient of static friction using the derived equations
  • Explore the effects of varying speeds on the required coefficient of friction
  • Study the implications of banking angles on vehicle dynamics
  • Review examples of similar problems involving banked curves and friction
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators seeking to enhance their understanding of forces on banked curves and friction in automotive contexts.

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Homework Statement


A curve with a 140m radius on a level road is banked at the correct angle for a speed of 20 m/s. If an automobile rounds this curve at 30 m/s, what is the minimum coefficient of static friction between tires and road needed to prevent skidding?

Homework Equations


F_fr = MkN
N = mgcosθ
∑F = ma
∑F_net-x = mv^2/r = Nsinθ

The Attempt at a Solution


I have drawn my xy coordinate system so that the x component is parallel to the curve, and , and found that the normal force is mgcosθ. However, I don't know how to combine my equations together to find an angle theta. Is finding an angle here even the proper approach if the problem does not ask for it? Should I be doing something else instead?
 
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Hello PhysicsDerp,

Welcome to Physics Forums! :smile:

PhysicsDerp said:

Homework Statement


A curve with a 140m radius on a level road is banked at the correct angle for a speed of 20 m/s. If an automobile rounds this curve at 30 m/s, what is the minimum coefficient of static friction between tires and road needed to prevent skidding?

Homework Equations


F_fr = MkN
Not sure what that equation is. Oh, wait. I get it: The force of friction, Ffr = μkN, where N is the normal force. Okay, that's good. :approve:

N = mgcosθ
Not so fast (see below).

∑F = ma
Yes, Newton's second law is important for this one. :smile:

∑F_net-x = mv^2/r = Nsinθ
Be careful there. It's not quite that simple.

The Attempt at a Solution


I have drawn my xy coordinate system so that the x component is parallel to the curve, and ,
That should work out. Personally, I would have simply stuck with the x-axis on the horizontal direction and the y-axis on the vertical.

I don't think changing the coordinate system such that the x-axis is parallel to the ramp will make the problem any easier. But whatever the case, it should still allow you to find the correct answer.

and found that the normal force is mgcosθ.
Something is not quite right there.

The normal force would be mgcosθ if the car were just sitting there at rest. But it's not; it's accelerating around the curve. The normal force is more complicated than that (regardless of the choice of coordinates).

However, I don't know how to combine my equations together to find an angle theta. Is finding an angle here even the proper approach if the problem does not ask for it? Should I be doing something else instead?

You might want to take another look at your free body diagram. Make sure that you have the following forces outlined on it:
  • The force due to gravity
  • The normal force
  • The force of friction
  • The resultant force (i.e., the net force)
The resultant (net) force is equal to ma. This is the force equal to the centripetal force.
 
Last edited:

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