Chemistry Calculating Moles Using Volume and Molarity

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The discussion focuses on calculating the number of moles of barium nitrate using its volume and molarity. The user presents the balanced equation for the reaction and provides the volume (5 mL) and molarity (0.1 M) of barium nitrate. They apply the molarity formula, rearranging it to find moles, and calculate 0.0005 moles. The user expresses uncertainty about the correctness of their approach but arrives at a plausible solution. The calculation appears accurate based on the provided data and formula.
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Homework Statement



Was wondering if I did this right, don't know if I used the right equation.

Equation: Ba(NO3)2 + Na2(SO4) = Ba(SO4) + 2Na(NO3)
Volume of barium nitrate: 5mL
Molarity of Barium nitrate: .1M

Homework Equations



Molarity = moles/L

The Attempt at a Solution



.1M = x/.005L
.1x.005 = x
x= .0005 moles
 
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