Calculating Muzzle Speed with Embedded Bullet and Friction

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To calculate the muzzle speed of the bullet, apply the principles of conservation of momentum and energy. The bullet embeds in the block, creating an inelastic collision where momentum is conserved. After the collision, the block and bullet experience friction, which decelerates them as they move 18 meters before stopping. The frictional force can be calculated using the coefficient of friction, allowing for the determination of the deceleration. By combining these calculations, the initial muzzle speed of the bullet can be derived from the final velocity of the block-bullet system.
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i really need help with this- i partially understand it, but I'm not sure exactly how to do this problem.

a 44 g bullet strikes and becomes embedded in a 1.54 kg block fo wood placed on a horizontal surface just in front of the gun. if the coefficient of friction between the block and surface is equal to .28 and the impact drives the block a distance of 18 m before it comes to rest, what was the muzzle speed of the bullet?

can anyone help?
 
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use energy and momentum. what collison happens?
 
i realize that impulse equals force times the change in time, which equals momentum, but i don't know how to apply these when there are two masses, and the coefficient of friction is involved. in all my previous problems, the necessary info was less and easier... :-\
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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