Finding the expression for momentum.

Click For Summary

Homework Help Overview

The problem involves a bullet of mass m being fired into a block of mass M at rest, resulting in the block sliding a distance d across a surface with a given coefficient of kinetic friction μk. The objective is to find an expression for the bullet's speed vbullet in terms of the provided variables.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the definitions of momentum and the variables involved, specifically the relationship expressed by p=mv. There is also a discussion about the implications of the bullet embedding into the block and how this affects the momenta of both objects.

Discussion Status

The discussion is ongoing, with participants exploring the relationships between the bullet and block's momenta and questioning the original poster's assumptions. Some guidance has been offered regarding the definitions of momentum and the implications of the collision.

Contextual Notes

There is a lack of clarity on how to relate the forces acting on the block after the collision, and the original poster has not provided a complete setup for the problem. The discussion is also constrained by the need to express the answer in terms of specific variables and constants.

aracali
Messages
5
Reaction score
0

Homework Statement


A bullet of mass m is fired into a block of mass M that is at rest. The block, with the bullet embedded, slides distance d across a horizontal surface. The coefficient of kinetic friction is μk.

Find an expression for the bullet's speed vbullet.
Express your answer in terms of the variables m, M, μk, d, and appropriate constants.

Homework Equations


p=mv

After that I have nothing.
 
Physics news on Phys.org
Think a bit further. Why did you write p=mv? what are p, m, v?
 
ehild said:
Think a bit further. Why did you write p=mv? what are p, m, v?
p= momentum
m=mass
v=velocity

I also forgot to include:
Faverage(Δt)=mΔv=Δp=J
 
You have two objects, the bullet and the block. Both have momentums. What happens with the momentums when you fire a bullet into a block and the bullet is embedded in the block?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
14K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
21
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
335
Views
17K
Replies
12
Views
2K