Calculating Net Dipole Moment for Water - What Am I Doing Wrong?

[HelloCthulhu]

Greeting PF!

http://chemwiki.ucdavis.edu/Physical_Chemistry/Atomic_Theory/Dipole_Moments

On the website above, I found an equation for the dipole moment of water:

"...the net dipole moment =2(1.5)xcos(104.5/2)=1.84 D."

I understand how to calculate the bond dipole. But after calculating for the net dipole, I keep getting the same wrong answer: -1.20606

Please tell me what I'm doing wrong! Thank you so much for your assistance! :]

 

[Borek]

Have you tried to switch your calculator to DEG?

 

[HelloCthulhu]

I'm using an iPhone app. It has a tab for trig where I found cos(, so I don't think I have to switch modes. I've also used Google's scientific calculator and received the same answer. Was your answer 1.84?

 

[Borek]

But you know the difference between degrees and radians, do you?

 

[HelloCthulhu]

Oh, wow. Totally screwed that up. Changed 104.5 radians and now I've got 1.836. Thanks Borek! :D