Calculating Net Gravitational Force Between Multiple Objects

AI Thread Summary
To calculate the net gravitational force on a 50.0 kg object positioned between a 200 kg and a 500 kg object, the gravitational constant (G) of 6.674 x 10^-11 N(m/kg)^2 must be used. The forces should be calculated separately for both the 200 kg and 500 kg objects, rather than subtracting their masses. The correct approach involves applying the formula F = G(m1*m2)/r^2 for each pair and then using vector addition to find the net force. The initial confusion stemmed from using the wrong value for G and misunderstanding the calculation method. Properly calculating each force and combining them as vectors will yield the correct net gravitational force.
phyhelpme
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Confused :(

Homework Statement


A 200 kg object and a 500 kg object are separated by 0.500 m. Find the net gravitational force exerted by these objects on a 50.0 kg object placed midway between them.
 
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I have:
F= Gm1m2/r^2
F= G(50.0kg)(500kg-200kg)/0.25m^2 =240000N toward 500kg

I feel that I have it setup right but for some reason when I calculate I get 2400000 which seems wrong to me.
 
phyhelpme said:
I have:
F= Gm1m2/r^2
F= G(50.0kg)(500kg-200kg)/0.25m^2 =240000N toward 500kg

I feel that I have it setup right but for some reason when I calculate I get 2400000 which seems wrong to me.

What value have you used for G?
 
DaveC426913 said:
What value have you used for G?


9.8 m/s^2
 
phyhelpme said:
9.8 m/s^2

That's little g. You want http://en.wikipedia.org/wiki/Gravitational_constant" .
 
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Any advice on how I find it?
 
Your working the same problem?
 
qwerty11 said:
Any advice on how I find it?


The easiest way, I would think, would be to click on the link DaveC provided under 'big G'. :smile:
 
  • #10
dotman said:
The easiest way, I would think, would be to click on the link DaveC provided under 'big G'. :smile:

If it was a snake it would have bitten me.

So G is 6.674 x 10^-11N (m/kg)^2 correct?

That would mean my equation is:
F= 6.674 x 10^-11(50.0kg)(500kg-200kg)/0.25m^2 =1.60176 x 10^-5N toward 500kg?
 
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  • #11
No, you don't subtract the masses.

Calculate the forces separately, between the 200&50 kg masses, and then between the 500&50 kg masses. Then use vector addidtion to add these two forces together. Important: add the forces as vectors, don't just add the two numbers together.
 
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