Calculating Normal Force on a Hill for a Bike and Rider - Quick HW Answers

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SUMMARY

The discussion focuses on calculating the normal force acting on an 80 kg bike and rider at the top of a circular hill with a radius of 60 meters while traveling at a speed of 35 m/s. The correct calculation involves applying centripetal acceleration principles, leading to a normal force of 2418 N, which is a positive value indicating an upward reaction force. This contrasts with an incorrect initial answer of -849 N, which fails to account for the proper coordinate system and forces involved.

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  • Centripetal acceleration concepts
  • Normal-tangential coordinate system
  • Newton's second law of motion
  • Basic physics of circular motion
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Homework Statement

An 80KG(bike and rider) are going over the top of a hill shaped in a circle and arch is 60m. If moving at 35m/s at top of hill what's the size of the normal force on bike and rider.



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The Attempt at a Solution

-849N?
 
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well, for one you're going to have centripetal acceleration so when you apply the kinetic equation (using a normal-tangential coordinate system) you'll be able to get the answer pretty easily. I got N = 2418, which unlike your answer is positive indicating an upward reaction force (assuming you're coordinate system is positive upwards)
 

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