Calculating Number of Electrons for Positive Charge of 1X10-6

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SUMMARY

To achieve a positive charge of 1X10-6 Coulombs on a neutral isolating conducting sphere, 6.24X1012 electrons must be removed. This calculation is derived from the formula Fe=q/e, where 'q' represents the charge and 'e' is the elementary charge of an electron, approximately -1.602X10-19 Coulombs. The result indicates that the number of electrons removed is a positive value, confirming that the charge becomes positive upon removal.

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Homework Statement



How much electron must be remove from a neutral isolating conducting sphere to give it a positive charge of 1X10-6

Homework Equations



#e=q/e

The Attempt at a Solution



Fe=q/e

fe=1X10-6/-1.602X10-19

=6.24X1012


just wondering if the answer is -6.24.. or +..


thanks
 
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Number of electrons would always be positive, so it is +ve.
 

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