1. The problem statement, all variables and given/known data For the equation shown below: x2+2x+3 / (x2+9)(X-3) = Ax+B/(x2+9) + C/(x-3) Find A, B and C 2. Relevant equations 3. The attempt at a solution C = 1 B = 2 A = ? Find C which = 1 by putting x=3 and working out x2+2x+3/(x2+9), then multiply out equation to find A and B x2+2x+3 = C(X2+9) + (Ax+B)/(X-3) Combine terms to give: x2+9+Ax2-3Ax+Bx-3B = x2(1+A)+ x(B-3A) + 9 -3B if coefficients = 0 then x2 = 0 then A = -1 9-3B = 3 therefore B = 2 B-3A = 0 therefore A = 2/3 but I think this answer is wrong? I now have 2 answers for A? Any ideas please and thanks.