Calculating Peak Current in a Series RLC Circuit

[Twoism]

Homework Statement

A series RLC circuit consists of a 100 ohm resistor, a 0.10 H inductor, and a 100 micro farad capacitor. It is attached to a 120 V/60 Hz power line. What is the peak current, I?

Homework Equations

I=V/Z
Z=sqrt(R^2+(omegaL - (omegaC)^-1))
omega=2pif

The Attempt at a Solution

I=120/sqrt(100^2+(2pi(60)*.1 - (2pi(60)*100x10^-6)^-1)^2)=1.2
The program is saying it's wrong.
I'm confused what I'm doing wrong, exactly. I'm thinking the omega is wrong, but I don't know how I would get omega otherwise.
Thanks for your help.

 

[Twoism]

I eventually figured it out... apparently 120 V is the rms value, which they clearly do NOT indicate what-so-ever... so my value of I was really I rms, and they just wanted it in I. My answer times sqrt(2) gave me the correct answer.