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cstout
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Homework Statement
The Hubble Space Telescope orbits Earth 615 km above Earth's surface. What is the period of the telescope's orbit?
Homework Equations
T = 2(pi)r/v
The Attempt at a Solution
T = 2(pi)(6.37x10^6)/9.8
cstout said:Isn't 6.37 × 106 m the radius of the earth, or do I use another measurement.
A circular orbit is the path that an object follows around another object, where the distance between the two remains constant and the object travels at a constant speed.
The period of a circular orbit is the time it takes for an object to complete one full revolution around another object.
The period of a circular orbit is affected by the mass of the objects, the distance between them, and the gravitational force between them.
Yes, the period of a circular orbit can be changed by altering the speed or distance of the orbiting object, or by changing the mass of the objects.
The period of a circular orbit can be calculated using the formula T = 2π√(r³/GM), where T is the period, r is the distance between the objects, G is the gravitational constant, and M is the combined mass of the objects.