Calculating Potential Energy from Force for Non-Linear Systems

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Homework Help Overview

The discussion revolves around calculating potential energy from a given force function, specifically in the context of non-linear systems. The force is defined by the equation F(x) = αx - βx³, and participants are exploring the relationship between force and potential energy.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the integration of the force function to derive potential energy and question the limits of integration. There is also a focus on the significance of the integration constant and the choice of the zero-level for potential energy.

Discussion Status

Some participants have provided guidance regarding the integration constant and its physical implications, suggesting that the choice of zero-level for potential energy does not affect the overall physics of the problem. Multiple interpretations regarding the limits of integration and the implications of setting potential energy to zero at a specific point are being explored.

Contextual Notes

There is an ongoing discussion about the assumptions related to the integration limits and the physical relevance of the integration constant in the context of potential energy.

RubroCP
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Homework Statement
##F(x)=\alpha x-\beta x^3##
Relevant Equations
##-\frac{\mathrm{d}V(x)}{\mathrm{d}x}=F(x)##
If I have a force that behaves according to the formula ##F(x)=\alpha x-\beta x^3##, how can I get the potential energy from it? I know that:
$$-\frac{\mathrm{d}V(x)}{\mathrm{d}x}=F(x),$$
but what about the limits of the integration?
 
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The integration constant is not physical as it does not affect the force. It is up to you to choose the zero-level of the potential.
 
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Orodruin said:
The integration constant is not physical as it does not affect the force. It is up to you to choose the zero-level of the potential.
So can I say without loss of generality that for x = 0 the potential is also null?
 
Yes, this will not affect the physics.
 
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Orodruin said:
Yes, this will not affect the physics.
Thanks!
 

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