Calculating Power and Force in Cycling: Solving for Force in the Equation P=Fv

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Homework Help Overview

The discussion revolves around calculating power and force in the context of cycling, specifically using the equation P=Fv and its relation to another equation involving average power and distance. Participants are exploring how to express force in terms of various factors, including air resistance and the cyclist's applied force.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to relate different equations involving power and force, questioning how to accurately express force when considering both air resistance and the cyclist's effort. There is discussion about the implications of assuming constant speed and how that affects the net force calculation.

Discussion Status

The discussion is ongoing, with participants offering insights into the relationship between force and power. Some have suggested that if speed is constant, the net force may primarily be due to air resistance, while others are questioning the validity of assuming constant speed given the information available.

Contextual Notes

There is a noted constraint regarding the lack of information if speed varies significantly, which impacts the ability to calculate the net force accurately.

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Homework Statement
Professional cyclists typically travel at 40 km/h during races. Air resistance produces a force on a cyclist that obeys a law~F(v) =−bv^2 opposite the direction of motion and proportional the speed squared. The coefficient b differs from person to person. The average power Pave that a well-trained cyclist can maintain for Nh hours is roughly Pave^2= 3(Pftp^2)/Nh, where Pftp is the maximum power she can produce without lactic acid accumulation. Solve for the average speed the cyclist can maintain in terms of Pftp and the distance of the race.
Relevant Equations
P=Fv
OK, so I tried to relate the equation P=Fv to the given equation that Pave^2= 3(Pftp^2)/Nh. I put Nh in terms of distance to satisfy the requirement that the answer should be in terms of Pftp and distance by saying Nh = distance/Vave. I also substituted Pave with Fvage.
(FVage)^2 = 3(P^2ftp)Vave/d ---> Vave = 3(^2Pftp)/Fd

My problem is I don't know what to substitute force with. The force is not only the -bv^2 from air resistance, it is also the force applied by the cyclist. With this, how would I find force?
 
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oisdas said:
The force is not only the -bv^2 from air resistance, it is also the force applied by the cyclist.
Taking the speed as constant, what is the net force?
 
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haruspex said:
Taking the speed as constant, what is the net force?
If speed was constant, the net force would just be from air resistance. However, how would I assume that speed is constant?
 
oisdas said:
how would I assume that speed is constant?
Because if it varies significantly you do not have enough information.
 
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haruspex said:
Because if it varies significantly you do not have enough information.
I see, thank you! With this, I will set the force the bicyclist is applying = Fair since a=0 and get F= -bv^2.
 

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