Power of a Force: Find Power from Fv in 3s

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Homework Help Overview

The problem involves calculating the power of a force given its vector representation and the displacement over a specific time interval. The subject area pertains to vector mechanics and power calculations in physics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to express velocity as a vector and consider the dot product of force and velocity. There are differing attempts to calculate power, with some participants questioning the correctness of the initial power equation used.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the power calculation. Some guidance has been provided regarding the vector nature of the problem and the correct application of the power formula.

Contextual Notes

There appears to be confusion regarding the application of the power formula and the representation of vectors. The original poster and others have noted discrepancies in their calculated power values.

hendrix7
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Homework Statement


A force of 2i + 5j moves from (2,5) to (4,7) in 3 seconds. Find the power of the force.

Homework Equations


Power = Fv

The Attempt at a Solution


|F| = sqrt 29
v = (sqrt 8)/3
Power = 5.077 w
 
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You need to write the velocity as a vector and take the dot product of F and v.
 
B
hendrix7 said:

Homework Statement


A force of 2i + 5j moves from (2,5) to (4,7) in 3 seconds. Find the power of the force.

Homework Equations


Power = Fv

The Attempt at a Solution


|F| = sqrt 29
v = (sqrt 8)/3
Power = 5.077 w
But i am getting 4.66
 
hendrix7 said:
Power = Fv
As @phyzguy points out, that equation is not correct. In vectors, ##P=\vec F.\vec v=|\vec F| |\vec v| \cos(\theta)##, where θ is the angle between the vectors.
 
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Thank you guys for putting me straight.
 

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