Calculating Pressure Difference Between Sections 1 and 2

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Homework Help Overview

The discussion revolves around calculating the pressure difference between two sections of a fluid system, specifically focusing on the relationship between pressure and fluid column height, as well as head loss in a theoretical context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Bernoulli's principle to find the pressure difference and questions how to calculate head loss given a specific height difference. Some participants provide feedback on the correctness of the initial equation and discuss the relationship between pressure difference and head loss.

Discussion Status

The discussion is active, with participants providing insights on the equations involved. There is a clarification regarding the theoretical nature of the head loss mentioned, and participants are exploring the relationship between pressure difference and fluid height.

Contextual Notes

There is mention of specific values for diameters and density, as well as assumptions regarding friction and discharge coefficients. The head loss is noted as theoretical, indicating a potential gap in practical application.

timothy1875
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Trying to calculate pressure difference between sections 1 and 2.
1=32mm 2=20mm
density = 1000 kg/m^3

I have done P1-P2 = 1/2 density x (vi^2 - vj^2)

Is this right?

How do I now find head loss if difference between 1 and 2 were 45mm ?

45/density x gravity ?

Thanks,
 
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Your equation for P1 - P2 looks OK (in the absence of friction and assuming the discharge coefficient = 1).

The relation between static pressure difference and fluid column height ("head loss") is:

P2 - P1 = density X g X h1 - h2. Is your head loss 45 mm or was that just an example?
 
Ye 45mm is the head loss but it's theoretical and not related to the initial equation. Would the formula be h1 - h2 = p2 - p1 / density x g ?

Thanks for your help
 
timothy1875 said:
Ye 45mm is the head loss but it's theoretical and not related to the initial equation. Would the formula be h1 - h2 = p2 - p1 / density x g ?

Thanks for your help
Yes.
 

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