Calculating Pressure Inside a Water Mist Droplet

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Homework Help Overview

The discussion revolves around calculating the gauge pressure inside a spherical droplet of water mist with a specified diameter and surface tension. Participants are exploring the application of the relevant formula and the conversion of pressure units.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to apply the formula for gauge pressure based on surface tension and radius. There are questions regarding the accuracy of the calculated pressure and the correct conversion between Pascals and atmospheres.

Discussion Status

Some participants have confirmed the use of the correct formula and discussed the significance of unit conversion. There is an ongoing exploration of the calculated values, with no explicit consensus on the final answer yet.

Contextual Notes

Participants are working under the constraints of specified values for diameter, surface tension, and pressure unit definitions as provided in the problem statement.

Derek1997
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Homework Statement


What's the gauge pressure inside a droplet of water mist of diameter 0.1 mm (radius 0.05 mm), assuming that the droplet is spherical? Use a water-air surface tension of 0.07 Jm\(^{-2}\) and specify your answer in bar /atmospheres (where 1 atmosphere pressure is \(1 \times 10^5\) Pa.

Homework Equations


delta P= 2*0.07/r (in meters)

The Attempt at a Solution


I subed the value inside the equation and i got 3000pa.. which is 3atm? am i right?
 
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Derek1997 said:

Homework Statement


What's the gauge pressure inside a droplet of water mist of diameter 0.1 mm (radius 0.05 mm), assuming that the droplet is spherical? Use a water-air surface tension of 0.07 Jm\(^{-2}\) and specify your answer in bar /atmospheres (where 1 atmosphere pressure is \(1 \times 10^5\) Pa.

Homework Equations


delta P= 2*0.07/r (in meters)

The Attempt at a Solution


I subed the value inside the equation and i got 3000pa.. which is 3atm? am i right?
It looks like you've chosen the correct formula to use, and your result in Pascals looks good to me for one significant figure of accuracy. Note however that an atm is not 1000 Pa; One atm is to be taken as 105 or 100,000 Pa according to the definition you're given in the problem statement.
 
so 0.03?
 
Derek1997 said:
so 0.03?
Yes, that looks like a good value. Be sure to always specify units on any values that you present!
 

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