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Pressure inside a soap bubble just under surface

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  1. Dec 28, 2015 #1
    1. The problem statement, all variables and given/known data
    What should be the pressure inside a small air bubble of 0.1,, radius,situated just below the surface? st of water=7.2 *10-2 and atmospheric pressure=1.013*105.

    2. Relevant equations


    3. The attempt at a solution
    I am of the understanding that the pressure inside the bubble is the sum of the surrounding pressure and the excess pressure( 4s/r). But what I don't understand is the surrounding pressure. Should I take the atmospheric pressure? But since it's just below the surface,the top of the bubble would be exposed to atmospheric pressure and the rest of the bubble to whatever pressure the water exerts( I don't think i'm right, I need help). So which pressure is it that I take for external?
     
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  3. Dec 28, 2015 #2

    haruspex

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    Have you calculated how much difference that makes?
    There is another difference between a bubble above the surface and one under the surface which might have rather more significance.
     
  4. Dec 29, 2015 #3
    if a bubble was under the surface, the pressure inside the bubble would be 4s/r + the hydrostatic pressure at that height( Pa+hρg).
    I am unable to understand what exactly you mean by difference. Since the bubble is just below the surface,will the second term reduce to just Pa?
     
  5. Dec 29, 2015 #4

    haruspex

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    I asked if you had calculated how much difference it makes taking into account that little extra hydrostatic pressure. I mean the numbers, not the algebraic expression. I suspect it is negligible.
    There is rather an important difference in the forces. Do you know how the ##4\sigma/r## formula is derived? If you follow that through you should see why it is different.
     
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