Calculating Probability of Expected Return for Stock Portfolio

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Homework Help Overview

The discussion revolves around calculating the probability of an expected return for a stock portfolio consisting of two stocks, A and B, with given means and standard deviations. The original poster is seeking assistance in determining the probability that the portfolio will yield a return greater than zero.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to find the pooled mean and standard deviation of the portfolio's returns. There is mention of using z-scores to calculate probabilities, and some participants express uncertainty about the formulas for mean and variance.

Discussion Status

Participants are actively engaging with the problem, sharing formulas and calculations related to expected returns and variances. There is a mix of attempts to clarify statistical concepts and check assumptions about independence and the inclusion of weights in variance calculations. Some guidance has been offered regarding the use of standard formulas for expected values and variances.

Contextual Notes

There is a mention of the original poster's upcoming statistics exam, which may influence the urgency and nature of the discussion. Participants are also exploring the implications of statistical independence and covariance in their calculations.

anjunabeats
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Really stuck on this question.

Stock A has an expected return mean of 0.03 and standard deviation of 0.02
Stock B has an expected return mean of 0.02 and standard deviation of 0.01
Investor invests in 20 lots of stock A and 15 lots of Stock B (as in 4/7 in A and 3/7 in B)
What is the probability that the portfolio will have an expected return of > 0?

Im guessing you need to find the pooled mean and sd then use z score = X - mu / sd but I'm really not sure, hope somebody is willing to help :0
 
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So his total portfolio has a return distributed as Z = 20X + 15Y, where X and Y are the returns of stock A and B respectively. Since X and Y are normally distributed, so is Z. Therefore, as you say, start by finding the mean E(Z) and standard deviation σ(Z) of Z and calculate P(Z > 0).
 
Yeah I am not sure how to find the mean and standard deviation.
 
These are standard formulas, that you are probably supposed to know :)

For two normally distributed variables X and Y,
E(X + Y) = E(X) + E(Y)
Var(X + Y) = Var(X) + Var(Y)

There are straightforward generalisations to n variables. A particular version is that for a normally distributed variable X and integer n,
E(nX) = a E(X)
Var(nX) = n Var(X)
 
CompuChip said:
These are standard formulas, that you are probably supposed to know :)

For two normally distributed variables X and Y,
E(X + Y) = E(X) + E(Y)
Var(X + Y) = Var(X) + Var(Y)

There are straightforward generalisations to n variables. A particular version is that for a normally distributed variable X and integer n,
E(nX) = a E(X)
Var(nX) = n Var(X)

So for E(X + Y) = E(X) + E(Y)
E (X + Y) = 4/7 (0.03) + 3/7 (0.02) = 9/ 350 = 0.025714

and for Var(X + Y) = Var(X) + Var(Y)

Var (X + Y) = 0.02^2 + 0.01^2 = 1/2000
Standard deviation = 0.0223606

We are finding P (X > 0)

then for z = X - Mu/ sd
= 0 - 0.025714 / 0.0223606
= -1.149969

0.0668 + 0.5 = 56.68% chance that return > 0?
Does this look okay Compuchip?
 
Last edited:
I was searching on the internet and just found that Var(X + Y) = Var(X) + Var(Y) + 2COV(X,Y) therefore the above is most likely wrong.

How would i find the covariance of stocks A and B? Is there a quick way?
 
Yes, noticing that both variables are statistically independent, for example :P

Also, shouldn't you include the 4/7 and 3/7 in the variance? You don't want Var(X + Y), but Var(4/7 X + 3/7 Y), don't you?
 
found out we can find the sd using

root (sd1/number of stocks + sd2/number of stocks)
 
Except that the sd1 and sd2 in that formula should be squared.
And that, too, is exactly what I told you ;)
 
  • #10
Well i have my stats exam tommorow thanks for the help compuchip, really appreciated ciao.
 

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