Calculating Probability using the Poisson Distribution

[haruspex]

The probability of no arrivals in (9:10, 9:50) is P(Y=0)=e^-4/3=0.264

Right, so what is the probability of at least 1 arrival in (9:10, 9:50) ?

 

[sol59]

Right, so what is the probability of at least 1 arrival in (9:10, 9:50) ?

1-0.264=0.736

 

[haruspex]

1-0.264=0.736

Good. So put it all together. What is the probability of no arrivals in (9:00, 9:10) and at least one in (9:10, 9:50)?

 

[sol59]

Good. So put it all together. What is the probability of no arrivals in (9:00, 9:10) and at least one in (9:10, 9:50)?

0,736*0.716=0.527

 

[haruspex]

0,736*0.716=0.527

You got there!

 

[sol59]

You got there!

Thank you so much for your help! I've managed to solve all other problems but this one was too difficult for me:) Thanks again:)!