Probability: Poisson distribution involving customer arrivals

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Homework Help Overview

The discussion revolves around a probability problem involving the Poisson distribution, specifically focusing on customer arrivals at two stores, A and B. The problem presents two questions regarding the probabilities of customer distributions between the stores.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of the Poisson distribution to determine probabilities related to customer arrivals in two stores. There are attempts to derive expressions for the probabilities of non-zero customers in store A and zero customers in store B, as well as for specific customer counts.

Discussion Status

Some participants have provided initial attempts at solutions, with one participant questioning the correctness of the first answer while affirming the second. There is ongoing exploration of the correct formulation for the first question, and a request for a concise form of the summation has been made.

Contextual Notes

Participants are discussing the implications of the Poisson distribution's properties and the assumptions regarding customer entry probabilities being equal for both stores.

sanctifier
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Homework Statement



There are two stores A and B.

Customers can equally enter one of the two stores, i.e., for a specific customer, the probabilities she enters store A or B both are 0.5.

If the total number of customers in two stores has the Poisson distribution of parameter λ, then

Question 1: What is the probability that the number of customers in store A is non-zero and store B has no customers;

Question 2: What is the probability that the number of customers in store A is exactly 2 and store B has no customers.

Homework Equations



Poisson distribution: p(x)=λx/x! * e

The Attempt at a Solution



Answer 1: (1-p(0))*(0.5+0.52+0.53+...)=1-e
Comment: The probability that there are some customer in some store is 1 - p(0), then the probability that x customers entered store A is 0.5x, hence their product should yield the desired answer?

Answer 2: p(2)*0.52
Comment: Similar strategy as answer 1.

Are these correct?

Thank you in advance!
 
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sanctifier said:

Homework Statement



There are two stores A and B.

Customers can equally enter one of the two stores, i.e., for a specific customer, the probabilities she enters store A or B both are 0.5.

If the total number of customers in two stores has the Poisson distribution of parameter λ, then

Question 1: What is the probability that the number of customers in store A is non-zero and store B has no customers;

Question 2: What is the probability that the number of customers in store A is exactly 2 and store B has no customers.


Homework Equations



Poisson distribution: p(x)=λx/x! * e

The Attempt at a Solution



Answer 1: (1-p(0))*(0.5+0.52+0.53+...)=1-e
Comment: The probability that there are some customer in some store is 1 - p(0), then the probability that x customers entered store A is 0.5x, hence their product should yield the desired answer?

Answer 2: p(2)*0.52
Comment: Similar strategy as answer 1.

Are these correct?

Thank you in advance!

You answer to (2) is correct, but your answer to (1) is not.
 
Ray Vickson, thank you for your replay.

If answer (2) is correct, then answer (1) is p(1)*0.5 + p(2)*0.52 + p(3)*0.53 + ...

Is this correct?

If it is, then is there a concise form of the summation?
 
sanctifier said:
Ray Vickson, thank you for your replay.

If answer (2) is correct, then answer (1) is p(1)*0.5 + p(2)*0.52 + p(3)*0.53 + ...

Is this correct?

If it is, then is there a concise form of the summation?

Yes, and yes. For the latter, see https://www.efunda.com/math/exp_log/series_exp.cfm .
 
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