Calculating Pump Power for Well Water Removal

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Homework Help Overview

The problem involves calculating the power of a pump used for removing water from a well, which has specific dimensions and a defined volume of water. The original poster seeks clarity on determining the mean displacement of the center of gravity in this context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for a clear understanding of the mean displacement of the center of gravity and suggest visual aids like sketches. There are mentions of using integration and considering different cases of water removal to analyze the problem further.

Discussion Status

The discussion is ongoing, with participants exploring various methods to conceptualize the problem. Some guidance has been offered regarding the use of sketches and integration, but there is no explicit consensus on the approach to take.

Contextual Notes

There is a focus on understanding the concept of mean displacement, with participants expressing the need for clarity on this aspect. The original poster has indicated that they have already created a sketch but still seek further explanation.

Akash47
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Homework Statement


A well has a diameter of 6 m and a height of 15 m.2/3 of volume of the well is filled with water.A pump can vacate 1/3 of volume of water from the well in 7 minutes 20 seconds.What is the power of the pump?

Homework Equations


W=mgh, P=W/t

The Attempt at a Solution


The question can be solved easily by using the given equations.But I don't know how I will find the mean displacement of center of gravity.Actually I don't have any idea about this (the part in bold line).So I want a clear concept about it.
 
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Why don't you try making a sketch of where the water is before and after the pumping process?
 
phyzguy said:
Why don't you try making a sketch of where the water is before and after the pumping process?
I am sure that you haven't understand my problem clearly .I have already made a sketch of the problem but I haven't any idea about mean displacement of center of gravity.I just want a clear concept about this and nothing else.
 
Akash47 said:
I am sure that you haven't understand my problem clearly .I have already made a sketch of the problem but I haven't any idea about mean displacement of center of gravity.I just want a clear concept about this and nothing else.
Have you tried thinking about it using a simple integration, and then comparing that to the answer you get by using the center of the water column for the mean displacement? Or even simpler, you don't have to set up the integration, just consider different cases with different "pieces" of the water being taken out separately. Start with one whole piece with the center of mass in the center of the water column, and lift that center up to ground level. Then cut the column in half, and do the same for the two separate water columns and their centers of gravity. Then do the case cutting the water column into 4 pieces, and so on... :smile:
 
Akash47 said:
I haven't any idea about mean displacement of center of gravity.I just want a clear concept about this and nothing else.
it means figuring out where the mass centre of the pumped water is before and after pumping and taking the vertical difference between the two.
 
haruspex said:
it means figuring out where the mass centre of the pumped water is before and after pumping and taking the vertical difference between the two.
Thanks.
 

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