Calculating radius from volume

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Discussion Overview

The discussion revolves around calculating the radius of a vessel from its volume, specifically using the formula V = PI * r^2 * 4r. Participants explore the necessary steps to rearrange this equation to solve for the radius given a volume of 20 liters.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant seeks clarification on how to derive the radius from the given volume, noting a missing step in their course material.
  • Another participant suggests converting liters to cubic meters and rearranging the equation to isolate r, presenting a method to calculate r as (V / (PI * 4))^(1/3).
  • A participant emphasizes the importance of understanding the process rather than just providing the answer, advocating for hints instead of direct solutions.
  • One participant expresses confusion over calculator functions for computing cube roots and seeks assistance on how to perform the calculation.
  • Another participant confirms the meaning of the notation ^(1/3) as the cube root and offers guidance on using a calculator.
  • A participant acknowledges their progress in understanding the problem after receiving help, indicating that they were close to the solution but needed assistance with rearranging the equation.

Areas of Agreement / Disagreement

The discussion reflects a mix of viewpoints, with some participants providing direct calculations while others emphasize the importance of understanding the underlying concepts. There is no consensus on a single method, as participants explore different approaches to the problem.

Contextual Notes

Participants mention the need to convert volume from liters to cubic meters, indicating a dependency on unit conversions. There are also unresolved questions regarding the use of calculator functions for cube roots.

Who May Find This Useful

This discussion may be useful for students working on similar volume-to-radius calculations in physics or engineering contexts, particularly those seeking to understand the mathematical rearrangement of formulas.

bluffreggie
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Hi all,

i am working through some worked examples for my course and there seems to be a step missing.

the step says

"the internal diameter of the vessel can be determined from"

V=PI*r^2*4r

Now all I am given is that the volume V is 20 litres. is there any way i can determine the radius from this?

The answer written is r=0.117m

Thanks for any help guys!
 
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Assuming the vessel is filled with water, do you know how many litres of water is in a cubic metre? Or how many ml makes up a cubic centimetre?
From there you need to be able to rearrange this equation to solve for r in terms of V
 
if I say x^3 = 8, is it ok to say x = 2
This problem is just like the one above

V = PI * 4 * r^3

or r^3 = V / ( PI * 4)

so r = ( V / (PI * 4) )^(1/3)

Another this to remember is V is given in liters so you have to convert it into m^3.
20 liters = .02 m^3

and if you plug the above equation in a calculator, you get r = 0.11675m

hope it helps
 
Or you could just answer the entire question...
Is it not better to give a few hints, so that the OP will understand how to do it themselves?
 
Ahh i forgot the like terms of the r^2 and r!
i can not seem to get it to work on my calculator.
I get for (V/Pi*4)) = 0.02/Pi*4 = 1.59*10-3
How do i use ^(1/3)?
Is it the abc function?
 
^(1/3) just means cube root, so is there a button with a 3 in a square root sign?
 
yeah got it just. thanks mate. That was just the front end of the question. the rest is straight forward just got hung up on the rearrangment side of it. i was close but not close enough!
 
Glad to help
 

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