Calculating Rank Pulley Forces with Newton's Equations

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    Forces Pulley rank
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Homework Help Overview

The discussion revolves around calculating forces in a system involving rank pulleys, specifically using Newton's equations. Participants are exploring the effects of friction, the setup of the problem, and the relationships between the masses involved.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants express confusion regarding the role of friction in the problem, with some suggesting to assume a frictionless surface. Others discuss the connections between the blocks and the pulley system, questioning how the forces and accelerations relate to each other.

Discussion Status

The conversation includes various attempts to derive equations for the forces and accelerations of the blocks. Some participants have provided guidance on the relationships between the tensions and accelerations, while others are still working through their calculations and interpretations.

Contextual Notes

There is an ongoing discussion about the assumptions made in the problem, particularly regarding the frictional forces and the ideal nature of the pulleys. Participants are also addressing the implications of the masses and their relationships in the context of the problem.

  • #31
ohhhhh wait a second i think i understand case A now
 
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  • #32
Ok so case A the acceleration is actually 9.8m/s^2
 
  • #33
So for big block = 2kg and small block = 1kg i have

A: acceleration = 9.8m/s^2
B: acceleration = 3.26m/s^2
C: acceleration = -6.55m/s^2
D: acceleration = -3.26m/s^2
E: acceleration = 0

so i put the ranking as A>B>E>D>C and it is incorrect
 
  • #34
isukatphysics69 said:
Ok so case A the acceleration is actually 9.8m/s^2
Why should it be 9.8 m/s2?
What is the tension? The tension accelerates the big box. What is the acceleration?
 
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  • #35
isukatphysics69 said:
So for big block = 2kg and small block = 1kg i have

A: acceleration = 9.8m/s^2
B: acceleration = 3.26m/s^2
C: acceleration = -6.55m/s^2
D: acceleration = -3.26m/s^2
E: acceleration = 0

so i put the ranking as A>B>E>D>C and it is incorrect
A is wrong. What do you mean with negative accelerations? Use the magnitude of the acceleration to rank them.
 
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  • #36
i am such an idiot i always rush things and make mistakes, so now i see that A is 4.9m/s^2
 
  • #37
Ok so the ranking is C > A > B = D > E
 
  • #38
Thank you for your patience ehild, i have completed the assignment finally.
 
  • #39
isukatphysics69 said:
Thank you for your patience ehild, i have completed the assignment finally.
You are welcome.
 
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