Calculating Rank Pulley Forces with Newton's Equations

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SUMMARY

The discussion centers on calculating the forces acting on a rank pulley system using Newton's equations, specifically the equation f=ma. Participants clarify that the surface can be assumed frictionless, allowing for simplified calculations. The conversation emphasizes the importance of understanding tension in the string and the relationship between the masses involved, particularly noting that the larger block's mass is twice that of the smaller block. Ultimately, participants derive the correct accelerations for various cases, leading to a final ranking of accelerations based on their calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with concepts of tension in strings
  • Basic knowledge of frictionless surfaces in physics
  • Ability to solve algebraic equations related to motion
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  • Study the implications of friction in pulley systems
  • Learn about the dynamics of non-ideal pulleys
  • Explore advanced applications of Newton's laws in complex systems
  • Investigate the effects of varying mass ratios on acceleration in pulley systems
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of Newton's laws in action.

  • #31
ohhhhh wait a second i think i understand case A now
 
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  • #32
Ok so case A the acceleration is actually 9.8m/s^2
 
  • #33
So for big block = 2kg and small block = 1kg i have

A: acceleration = 9.8m/s^2
B: acceleration = 3.26m/s^2
C: acceleration = -6.55m/s^2
D: acceleration = -3.26m/s^2
E: acceleration = 0

so i put the ranking as A>B>E>D>C and it is incorrect
 
  • #34
isukatphysics69 said:
Ok so case A the acceleration is actually 9.8m/s^2
Why should it be 9.8 m/s2?
What is the tension? The tension accelerates the big box. What is the acceleration?
 
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  • #35
isukatphysics69 said:
So for big block = 2kg and small block = 1kg i have

A: acceleration = 9.8m/s^2
B: acceleration = 3.26m/s^2
C: acceleration = -6.55m/s^2
D: acceleration = -3.26m/s^2
E: acceleration = 0

so i put the ranking as A>B>E>D>C and it is incorrect
A is wrong. What do you mean with negative accelerations? Use the magnitude of the acceleration to rank them.
 
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  • #36
i am such an idiot i always rush things and make mistakes, so now i see that A is 4.9m/s^2
 
  • #37
Ok so the ranking is C > A > B = D > E
 
  • #38
Thank you for your patience ehild, i have completed the assignment finally.
 
  • #39
isukatphysics69 said:
Thank you for your patience ehild, i have completed the assignment finally.
You are welcome.
 
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