Calculating Rate of Change in Graphs: Is it Just Gradient?

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The rate of change in a graph is equivalent to the slope or gradient at a specific point, which is mathematically represented by the derivative of the function. For linear graphs, this gradient remains constant, while non-linear graphs require calculus to determine the rate of change. The discussion highlighted some confusion over terminology, particularly the use of "gradient" versus "slope" or "derivative," with some participants noting regional differences in language. Ultimately, the derivative provides the necessary information to calculate the rate of change in any graph. Clarifying these terms can help avoid misunderstandings in mathematical discussions.
flo123
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how do you calculate the rate of change in a graph?? is it just the gradient??
 
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Since your "rate of change" sounds terribly vague,i'll assume that it means "the change in <<y>> corresponding to an infinitesimal change in <<x>>",which means the derivative of the function at a specific point.

Daniel.
 
dextercioby said:
Since your "rate of change" sounds terribly vague,i'll assume that it means "the change in <<y>> corresponding to an infinitesimal change in <<x>>",which means the derivative of the function at a specific point.

Daniel.

Usually a premise, whether assumed or not, is followed by a conclusion. You didn't address his question :smile:

The rate of change at a point on a graph is the slope or gradient at that given point. For linear graphs of form y = mx + b the gradient is constant throughout the graph, for others calculus is used to find the rate of change.
 
whozum said:
Usually a premise, whether assumed or not, is followed by a conclusion. You didn't address his question :smile:

Yes, he did when he said "which means the derivative of the function at a specific point." "Derivative" is what us Yanks call the "gradient".
 
HallsofIvy said:
Yes, he did when he said "which means the derivative of the function at a specific point." "Derivative" is what us Yanks call the "gradient".

In that case, its a run-on sentence :biggrin:, and that's why it doesn't make immediate sense.

I was taught math in the US and I've only heard gradient when it comes to vector fields. This is the only place I've heard gradient used instead of slope or derivative.
 
Thanks for the replies, sorry it has caused tension in this debate about my vague question, the derivative of an equation is the gradient simple really... and its a her not a he

plus what other answers other than the change in y and x, could there be on a graph??
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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