Calculating Ratio of Electrical Current to Light Speed: A Challenge!

Click For Summary
SUMMARY

The discussion focuses on calculating the ratio of the speed of electrical current in a 0.505m long wire to the speed of light, using a 2.2E7 Hz electrical oscillator. The correct formula for a closed tube is identified as f = v/2L, leading to a calculated speed of 22220000 m/s. The ratio of this speed to the speed of light (3E8 m/s) is determined to be approximately 0.074. The participants clarify the concept of nodes and antinodes in relation to standing waves in closed tubes.

PREREQUISITES
  • Understanding of wave mechanics and standing waves
  • Familiarity with the concepts of frequency and wavelength
  • Knowledge of electrical resonance in circuits
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of wave equations for closed tubes
  • Learn about electrical resonance and its applications in circuits
  • Explore the relationship between frequency, wavelength, and wave speed
  • Investigate the principles of standing waves in different mediums
USEFUL FOR

Students in physics, electrical engineers, and anyone interested in wave mechanics and electrical resonance calculations.

woaini
Messages
58
Reaction score
0

Homework Statement



If a 0.505m long wire is excited into its lowest electrical resonance by a 2.2E7 Hz electrical oscillator, what is the ratio of the speed of the electrical current to that of light? Assume that the wire is like a tube with both ends closed.

f=2.2E7
L=0.505
v=?

Homework Equations



f=nv/2L
f=v/λ


The Attempt at a Solution



How do I solve this problem if I do not have λ or n? How would the equations work?
 
Physics news on Phys.org
Hint: How would you find λ if this was a problem involving sound waves in an organ pipe? You would do a drawing showing a standing wave with nodes and antinodes then calculate the wavelength.
 
How do I know how any nodes and antinodes to draw?
 
The problem states "lowest electrical resonance"
 
Does that mean n=1?
 
It says the fundamental frequency for a closed cylinder is f=v/4L

Therefore the speed I determine using the formula is...

v= f*4L = 2.2E7 * 4 *0.505 = 444400000 m/s

And the ratio of it to the speed of light is:

444400000 m/s / 3E8 m/s = 0.148

Does this look correct?
 
It says the fundamental frequency for a closed cylinder is f=v/4L

I think that's the formulae for a cylinder with one end open and one closed.
 
So how do I determine the formula for something closed on both ends?
 
  • #10
"Closed ends on a tube form a node..."

Draw it?

If you looked at the link I gave earlier it shows a drawing for one end open and one end closed. You can see how the formula is derived from that drawing. Do a new drawing with both ends closed and apply same ideas.
 
  • #11
Oh I see, the formula should be f=v/2L
 
  • #12
22220000m/s is the new speed I get?
 
  • #13
Remember they ask for a ratio.
 
  • #14
Alright makes sense now.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
867
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
5
Views
3K
Replies
12
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K