Calculating Refractive Index for Extraordinary Ray in Calcite Crystal

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Homework Statement


A beam of light travels through a calcite crystal such that its wave vector makes an angle of 30degrees with the optic axis. Calculate the refractive index experienced by the extraordinary ray if the relative dielectric constants for light polarized parallel and perpendicular to the optic axis are 2.208 and 2.749, respectively.


Homework Equations


Perhaps Snell's law? : n1 sin(theta1) = n2 sin(theta2)
Should I set it as Brewsters angle?

The Attempt at a Solution



I've also tried square-rooting 2.749 which gives me a similar answer to the actual solution.

The actual solution should be 1.61
 
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Could this be to do with total internal reflection in a polarizing beam-splitter?