Calculating Resistance for Charging a Battery Circuit Using Ohm's Law

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SUMMARY

The discussion focuses on calculating the resistance needed to charge a battery circuit using Ohm's Law, specifically targeting a charging current of 10mA. Participants confirm that a resistor should be placed in parallel with the diode to achieve this current. The voltage drop across the resistor is assumed to be 3V, allowing the battery to maintain a voltage of 12V. The key equation used is Ohm's Law: V=IR.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Basic knowledge of electrical circuits
  • Familiarity with battery charging principles
  • Experience with circuit diagrams and components
NEXT STEPS
  • Calculate resistance values using Ohm's Law for different current levels
  • Explore the effects of resistor placement in parallel circuits
  • Research battery charging circuits and their components
  • Learn about diode characteristics and their impact on circuit performance
USEFUL FOR

Electronics students, hobbyists designing battery charging circuits, and engineers working with DC power supplies.

dancergirlie
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Homework Statement



Make a modification so that the battery is charged by the DC supply at a current of 10mA

**See attached diagram**

Homework Equations





The Attempt at a Solution



Well I know that I would put in a resistor in parallel with the diode. However, I don't know how I would solve for the resistance.

I'm assuming that I would use Ohm's law:

V=IR where I=10mA, and I don't know what the voltage drop across the resistor would be... would it be 3V so that the battery drops 12 volts?

Any help would be great!
 

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dancergirlie said:

Homework Statement



Make a modification so that the battery is charged by the DC supply at a current of 10mA

**See attached diagram**

Homework Equations





The Attempt at a Solution



Well I know that I would put in a resistor in parallel with the diode. However, I don't know how I would solve for the resistance.

I'm assuming that I would use Ohm's law:

V=IR where I=10mA, and I don't know what the voltage drop across the resistor would be... would it be 3V so that the battery drops 12 volts?

Any help would be great!

Yes, that is correct.
 
thanks for confirming :D
 

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