Calculating Resistance in a Circuit with Unknown Components

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Homework Help Overview

The discussion revolves around calculating the resistance of an unknown component in a circuit, specifically in part b of a homework problem. Participants are exploring the relationships between voltage, current, and resistance in the context of Ohm's law.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the current flowing through various components, questioning how to calculate the unknown resistance based on given voltages and resistances. There are attempts to clarify the relationship between the voltmeters and the unknown resistor.

Discussion Status

The discussion is ongoing, with participants providing insights into the calculations and questioning the roles of different components in the circuit. Some guidance has been offered regarding the calculation of currents through the voltmeters and their implications for the unknown resistance.

Contextual Notes

There are uncertainties regarding the values of the resistances and the configuration of the circuit, particularly concerning the role of voltmeter V2 and its impact on the calculations for the unknown resistance.

ravsterphysics
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Homework Statement


I understand part a, but not part B.
circuit-jpg.110596.jpg


Homework Equations

The Attempt at a Solution


For part b) the PD across the resistor is 2V, but we don't know the current so we can't calculate using ohm's law eqn.

And because the new resistor's resistance is unkown, how do we actually calculate it?
 

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You've not actually said what the question is for part b, but if it's to determine the resistance R that isn't difficult. You can calculate the currents through meter V1 and through V2, so the current through the unknown resistance will be the difference between those.
 
Jonathan Scott said:
You've not actually said what the question is for part b, but if it's to determine the resistance R that isn't difficult. You can calculate the currents through meter V1 and through V2, so the current through the unknown resistance will be the difference between those.

shoot.

the question is: Calculate the value of R.
 
ravsterphysics said:
shoot.

the question is: Calculate the value of R.
For part b), what can you say about the current flowing through the circuit?
 
cnh1995 said:
For part b), what can you say about the current flowing through the circuit?

okay if V1 has voltage of 4v and its resistance is 1,000,000 ohms, then it's current must be 0.000004.

And this current must also flow through the resistor. Since total voltage is 6v, then this component must have voltage of 2V, so its resistance must be (2/0.000004) = 500,000 ohms, right?
 
ravsterphysics said:
okay if V1 has voltage of 4v and its resistance is 1,000,000 ohms, then it's current must be 0.000004.

And this current must also flow through the resistor. Since total voltage is 6v, then this component must have voltage of 2V, so its resistance must be (2/0.000004) = 500,000 ohms, right?
Right.
But that's not the final answer. You need to find R.
Edit: Resistance of V1 is 10MΩ. You have taken it as 1MΩ..
 
cnh1995 said:
Right.
But that's not the final answer. You need to find R.

okay the mistake I just realized is that the Mohms = 10,000,000 ohms so the current is I = 0.0000004 so resistance R is (2/0.0000006) = 5,000,000

but you're saying that's not the value of R?? But isn't the new component R??
 
ravsterphysics said:
okay the mistake I just realized is that the Mohms = 10,000,000 ohms so the current is I = 0.0000004 so resistance R is (2/0.0000006) = 5,000,000
Yes I had edited my post immediately after posting..
cnh1995 said:
Right.
But that's not the final answer. You need to find R.
Edit: Resistance of V1 is 10MΩ. You have taken it as 1MΩ..
ravsterphysics said:
but you're saying that's not the value of R?? But isn't the new component R??
R is the resistance used in place of the 10 ohm resistor. What about the resistance of voltmeter V2?
 
ravsterphysics said:
okay if V1 has voltage of 4v and its resistance is 1,000,000 ohms, then it's current must be 0.000004.

And this current must also flow through the resistor.

Is V2 removed for part b) ?
 
  • #10
cnh1995 said:
Yes I had edited my post immediately after posting..R is the resistance used in place of the 10 ohm resistor. What about the resistance of voltmeter V2?

CWatters said:
Is V2 removed for part b) ?

I'm still confused about what v2 has to do with the resistance of the component R? (and no, v2 is not removed)
 
  • #11
ravsterphysics said:
I'm still confused about what v2 has to do with the resistance of the component R? (and no, v2 is not removed)
What is the current flowing through the component resistance R? Is it same as that flowing through V1?
 
  • #12
ravsterphysics said:
I'm still confused about what v2 has to do with the resistance of the component R? (and no, v2 is not removed)
You need to consider the current flow. From the information available, you can calculate the current through V1 and the current through V2. The total of the currents through R and V2 must be equal to the current through V1, so the current through R is given by the difference of the two calculated currents, as I mentioned above. You then know both the potential across R and the current through it so you can calculate R.
 

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