Calculating Resistance of a Light Bulb

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SUMMARY

The discussion focuses on calculating the resistance of a light bulb using Ohm's Law. Participants measured a voltage drop of 2.25V across the bulb and a current of 0.24A flowing through it. The resistance was calculated using the formula R = ΔV/I, confirming that the voltage reading from the multimeter (2.25V) is the correct value to use. The calculated resistance values were 9.3 ohms and 3.13 ohms depending on the voltage interpretation, with the consensus being to use the direct measurement from the multimeter.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Basic knowledge of electrical measurements (voltage and current)
  • Familiarity with using a multimeter
  • Concept of voltage drop across a component
NEXT STEPS
  • Learn how to use a multimeter for accurate voltage and current measurements
  • Study the principles of series and parallel circuits
  • Explore advanced applications of Ohm's Law in circuit analysis
  • Investigate the effects of resistance on electrical components
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Students studying physics, electrical engineering enthusiasts, and anyone interested in practical applications of Ohm's Law in circuit analysis.

Kryttle
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Homework Statement


Hook up a round bulb to two D batteries. Measure the voltage drop across the bulb. Measure the current flowing through the bulb. Calculate the resistance of the bulb. V=2.25v; I=0.24A


Homework Equations


R=deltaV/I


The Attempt at a Solution


Is the "V" in the equation the number the multimeter gave me (2.25v) or do I use 3.0v-2.25v=0.75? In the first case R=9.3. Using 0.75v R=3.13.
 
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Welcome to PF!

Hi Kryttle! Welcome to PF! :wink:
Kryttle said:
Measure the voltage drop across the bulb.

Is the "V" in the equation the number the multimeter gave me (2.25v) …

Yes. :smile:

In V = IR (Ohm's Law), the https://www.physicsforums.com/library.php?do=view_item&itemid=301" drop and the resistance are both measured across the (same) component. :wink:
 
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